(2x^2-x-13)(x^2+1)=0

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Solution for (2x^2-x-13)(x^2+1)=0 equation: 


Simplifying
(2x2 + -1x + -13)(x2 + 1) = 0

Reorder the terms:
(-13 + -1x + 2x2)(x2 + 1) = 0

Reorder the terms:
(-13 + -1x + 2x2)(1 + x2) = 0

Multiply (-13 + -1x + 2x2) * (1 + x2)
(-13(1 + x2) + -1x * (1 + x2) + 2x2 * (1 + x2)) = 0
((1 * -13 + x2 * -13) + -1x * (1 + x2) + 2x2 * (1 + x2)) = 0
((-13 + -13x2) + -1x * (1 + x2) + 2x2 * (1 + x2)) = 0
(-13 + -13x2 + (1 * -1x + x2 * -1x) + 2x2 * (1 + x2)) = 0
(-13 + -13x2 + (-1x + -1x3) + 2x2 * (1 + x2)) = 0
(-13 + -13x2 + -1x + -1x3 + (1 * 2x2 + x2 * 2x2)) = 0
(-13 + -13x2 + -1x + -1x3 + (2x2 + 2x4)) = 0

Reorder the terms:
(-13 + -1x + -13x2 + 2x2 + -1x3 + 2x4) = 0

Combine like terms: -13x2 + 2x2 = -11x2
(-13 + -1x + -11x2 + -1x3 + 2x4) = 0

Solving
-13 + -1x + -11x2 + -1x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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